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If you were placed in some container, how much cubic meters of liquid would you displace?
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    is that proportional to my body mass?
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    If I was a perfect isosceles wedge of cheese, it would be much easier to work out. Unfortunately, the base of my triangular face, is not straight, but rather curved like a segment of a circle. If it was straight it would be 15cm long, and the distance from its midpoint to my tip would be 20cm, making the triangle 150 square centimetres. If we imagine the curved edge as a segment of a circle, we could use the formula (θ / 360°) × πr² - (1/2) r² sin θ = area of minor segment. If the arc was extended to be a full circle, the radius would be 10cm. The central angle of a sector in which the ends of the arc mark the arms of the angle, would be 120 degrees. So the area of the segment would be (120 / 360) × π × 10² - (1/2) × 10² sin(120) which equals to 76 cm squared. So the area of my triangular faces is 226cm². Multiply that by my height (12cm) to get 2712cm cubed. Converting that to metres cubed would be 0.27m³.

    Therefore, if I was placed in some container, I would displace 0.27m³ of water :)