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if you roll a 6-sided fair dice three times, what's the probability of rolling a 1 at least once?
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  • User icon
    91 in 216
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    1/6 with one die
    11/36 with two dice
    91/216 with three dice
    i think
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    Quickest way I can think of:
    Probability of avoiding rolling a 1 in one roll - 5/6
    Probability of avoiding rolling a 1 in three rolls - (5/6)^3
    Probability of failing to avoid rolling a 1 in three rolls, i.e. probability of rolling a 1 at least once in three rolls - 1-(5/6)^3 = 91/216

    And if that isn't enough, here's a python one-liner that counts all possible rolls of three dice to see how many contain at least one 1:
    print(len([i for i in itertools.product((1, 2, 3, 4, 5, 6), repeat=3) if 1 in i]))
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    (to resolve an argument)